This browser is no longer supported.
Upgrade to Microsoft Edge to take advantage of the latest features, security updates, and technical support.
![](data:image/svg+xml, %3Csvg xmlns='http://www.w3.org/2000/svg' height='64' class='font-weight-bold' style='font: 600 30.11764705882353px "SegoeUI", Arial' width='64'%3E%3Ccircle fill='hsl(204.8, 13%, 29%)' cx='32' cy='32' r='32' /%3E%3Ctext x='50%25' y='55%25' dominant-baseline='middle' text-anchor='middle' fill='%23FFF' %3EVS%3C/text%3E%3C/svg%3E)
How to convert Julian date column in normal date like colum contains 12490,12492 Julian dates
What is the expect result of these values? Or what is your definition of "Julian date"? (I looked it up in Wikipedia, but I am not sure that the article there has the same thing in mind as you have.)
![](data:image/svg+xml, %3Csvg xmlns='http://www.w3.org/2000/svg' height='64' class='font-weight-bold' style='font: 600 30.11764705882353px "SegoeUI", Arial' width='64'%3E%3Ccircle fill='hsl(211.20000000000002, 61%, 30%)' cx='32' cy='32' r='32' /%3E%3Ctext x='50%25' y='55%25' dominant-baseline='middle' text-anchor='middle' fill='%23FFF' %3EBS%3C/text%3E%3C/svg%3E)
simple expression:
declare @j int = 24263; -- 2024-09-19 in Julian
select dateadd(dy, (@j % 1000) - 1, dateadd(yy, @j/1000, cast('2000-01-01' as date)))